LeetCode
LeetCode 36 Valid Sudoku - Medium
36. Valid Sudoku -- Medium
36. Valid Sudoku — Medium
Problem
- Valid Sudoku -- Medium
Determine if a 9 x 9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
Each row must contain the digits 1-9 without repetition. Each column must contain the digits 1-9 without repetition. Each of the nine 3 x 3 sub-boxes of the grid must contain the digits 1-9 without repetition. Note:
A Sudoku board (partially filled) could be valid but is not necessarily solvable. Only the filled cells need to be validated according to the mentioned rules.
Example 1:
Input: board = [["5","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] Output: true
Example 2:
Input: board = [["8","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] Output: false Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
Constraints:
board.length == 9 board[i].length == 9 board[i][j] is a digit or '.'.
Solution
class Solution:
def isValidSudoku(self, board: List[List[str]]) -> bool:
used = set()
# 先枚举行,检查每行是否合法
for row in range(9):
used = set()
for col in range(9):
if not self.check_valid(board[row][col], used):
return False
# 先枚举列,检查每列是否合法
for col in range(9):
used = set()
for row in range(9):
if not self.check_valid(board[row][col], used):
return False
# 每个分块的左上角的坐标为(i * 3, j * 3)
for i in range(3):
for j in range(3):
used = set()
for row in range(i * 3, i * 3 + 3):
for col in range(j * 3, j * 3 + 3):
if not self.check_valid(board[row][col], used):
return False
return True
# 检查字符是否有冲突
def check_valid(self, c, used):
if c == '.':
return True
if c in used:
return False
used.add(c)
return True