LeetCode
LeetCode 528 Random Pick With Weight - Medium
528. Random Pick with Weight -- Medium
528. Random Pick With Weight — Medium
Problem
- Random Pick with Weight -- Medium
You are given an array of positive integers w where w[i] describes the weight of ith index (0-indexed).
We need to call the function pickIndex() which randomly returns an integer in the range [0, w.length - 1]. pickIndex() should return the integer proportional to its weight in the w array. For example, for w = [1, 3], the probability of picking the index 0 is 1 / (1 + 3) = 0.25 (i.e 25%) while the probability of picking the index 1 is 3 / (1 + 3) = 0.75 (i.e 75%).
More formally, the probability of picking index i is w[i] / sum(w).
Example 1:
Input ["Solution","pickIndex"] [[[1]],[]] Output [null,0]
Explanation Solution solution = new Solution([1]); solution.pickIndex(); // return 0. Since there is only one single element on the array the only option is to return the first element.
Example 2:
Input ["Solution","pickIndex","pickIndex","pickIndex","pickIndex","pickIndex"] [[[1,3]],[],[],[],[],[]] Output [null,1,1,1,1,0]
Explanation Solution solution = new Solution([1, 3]); solution.pickIndex(); // return 1. It's returning the second element (index = 1) that has probability of 3/4. solution.pickIndex(); // return 1 solution.pickIndex(); // return 1 solution.pickIndex(); // return 1 solution.pickIndex(); // return 0. It's returning the first element (index = 0) that has probability of 1/4.
Since this is a randomization problem, multiple answers are allowed so the following outputs can be considered correct : [null,1,1,1,1,0] [null,1,1,1,1,1] [null,1,1,1,0,0] [null,1,1,1,0,1] [null,1,0,1,0,0] ...... and so on.
Constraints:
1 <= w.length <= 10000 1 <= w[i] <= 10^5 pickIndex will be called at most 10000 times.
Solution
# Prefix Sum, Binary Search:
class Solution:
def __init__(self, w: List[int]):
self.w= w
for i in range(1, len(w)):
self.w[i]= self.w[i-1]+ self.w[i]
def pickIndex(self):
target= random.randint(1, self.w[-1])
start, end=0, len(self.w)
while start+1< end:
mid= start+ (end-start)//2
if self.w[mid]< target:
start= mid
elif self.w[mid]> target:
end= mid
else:
return mid
if self.w[start]>= target:
return start
return end