LeetCode 58 Length Of Last Word - Easy

58. Length Of Last Word — Easy

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Problem

58. Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word (last word means the last appearing word if we loop from left to right) in the string.

If the last word does not exist, return 0.

Note: A word is defined as a maximal substring consisting of non-space characters only.

Example:

Input: "Hello World" Output: 5

Solution

class Solution:
    def lengthOfLastWord(self, s: str) -> int:
        p, length = len(s), 0
        while p > 0:
            p -= 1
            # we're in the middle of the last word
            if s[p] != ' ':
                length += 1
            # here is the end of last word
            elif length > 0:
                return length
 
        return length